3.1.36 \(\int \frac {1}{(c \cos (a+b x))^{4/3}} \, dx\) [36]

Optimal. Leaf size=56 \[ \frac {3 \text {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {5}{6},\cos ^2(a+b x)\right ) \sin (a+b x)}{b c \sqrt [3]{c \cos (a+b x)} \sqrt {\sin ^2(a+b x)}} \]

[Out]

3*hypergeom([-1/6, 1/2],[5/6],cos(b*x+a)^2)*sin(b*x+a)/b/c/(c*cos(b*x+a))^(1/3)/(sin(b*x+a)^2)^(1/2)

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Rubi [A]
time = 0.01, antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.083, Rules used = {2722} \begin {gather*} \frac {3 \sin (a+b x) \, _2F_1\left (-\frac {1}{6},\frac {1}{2};\frac {5}{6};\cos ^2(a+b x)\right )}{b c \sqrt {\sin ^2(a+b x)} \sqrt [3]{c \cos (a+b x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(c*Cos[a + b*x])^(-4/3),x]

[Out]

(3*Hypergeometric2F1[-1/6, 1/2, 5/6, Cos[a + b*x]^2]*Sin[a + b*x])/(b*c*(c*Cos[a + b*x])^(1/3)*Sqrt[Sin[a + b*
x]^2])

Rule 2722

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*((b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1
)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin {align*} \int \frac {1}{(c \cos (a+b x))^{4/3}} \, dx &=\frac {3 \, _2F_1\left (-\frac {1}{6},\frac {1}{2};\frac {5}{6};\cos ^2(a+b x)\right ) \sin (a+b x)}{b c \sqrt [3]{c \cos (a+b x)} \sqrt {\sin ^2(a+b x)}}\\ \end {align*}

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Mathematica [A]
time = 0.03, size = 53, normalized size = 0.95 \begin {gather*} \frac {3 \cot (a+b x) \text {Hypergeometric2F1}\left (-\frac {1}{6},\frac {1}{2},\frac {5}{6},\cos ^2(a+b x)\right ) \sqrt {\sin ^2(a+b x)}}{b (c \cos (a+b x))^{4/3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(c*Cos[a + b*x])^(-4/3),x]

[Out]

(3*Cot[a + b*x]*Hypergeometric2F1[-1/6, 1/2, 5/6, Cos[a + b*x]^2]*Sqrt[Sin[a + b*x]^2])/(b*(c*Cos[a + b*x])^(4
/3))

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Maple [F]
time = 0.01, size = 0, normalized size = 0.00 \[\int \frac {1}{\left (c \cos \left (b x +a \right )\right )^{\frac {4}{3}}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(c*cos(b*x+a))^(4/3),x)

[Out]

int(1/(c*cos(b*x+a))^(4/3),x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*cos(b*x+a))^(4/3),x, algorithm="maxima")

[Out]

integrate((c*cos(b*x + a))^(-4/3), x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*cos(b*x+a))^(4/3),x, algorithm="fricas")

[Out]

integral((c*cos(b*x + a))^(2/3)/(c^2*cos(b*x + a)^2), x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{\left (c \cos {\left (a + b x \right )}\right )^{\frac {4}{3}}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*cos(b*x+a))**(4/3),x)

[Out]

Integral((c*cos(a + b*x))**(-4/3), x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(c*cos(b*x+a))^(4/3),x, algorithm="giac")

[Out]

integrate((c*cos(b*x + a))^(-4/3), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.02 \begin {gather*} \int \frac {1}{{\left (c\,\cos \left (a+b\,x\right )\right )}^{4/3}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(c*cos(a + b*x))^(4/3),x)

[Out]

int(1/(c*cos(a + b*x))^(4/3), x)

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